Technician Class License Lesson 2.3, Radio Equipment Basics

Posted on October 31, 2011 by

Here’s your video introduction to Lesson 2.3 of the Technician Class manual. The actual lesson is contained in the ARRL Ham Radio License Manual.
 

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2 Responses to Technician Class License Lesson 2.3, Radio Equipment Basics

  1. Dave says:
    June 18, 2015 at 1:30 pm

    Hi Daniel, there are two ways of approaching this. First, let’s consider the current through one resistor without respect to the other. The current is the voltage divided by the resistance, or 40/1000, or 40 milliamps. Now, there are two such resistors, so the total current is 2 x 40 mA, or 80 mA. Second, let’s consider two resistors in parallel. The formula for two resistors in parallel is R – R1*R2 / (R1 + R2), or 1000*1000 / 2000, or 1,000,000/2,000 or 1000/2 or 500 ohms. Going back to ohm’s law, the current through this parallel combination is the voltage divided by the resistance, or 40/500, or 0.08 A or 80 mA. I hope that helps. 73!

  2. Daniel Del Del Vecchio says:
    June 14, 2015 at 2:48 pm

    First, I want to congrats on the quality of your videos. they have been nothing but helpful and insightful for the study of my exam. I am doing my exam in Canada. I don’t get why this proper the math is 1000/2= 500 then use that 500 in the formula??

    Two resistors are connected in parallel and are connected across a 40 volt battery. If each resistor is 1000 ohms, the total current is:
    A) 40 amperes
    B) 80 amperes
    C) 80 milliamperes
    D) 40 milliamperes

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